How do you solve #x^2 - 4x = 5#?
1 Answer
May 10, 2018
Explanation:
#"since the coefficient of the "x^2" term is 1"#
#x^2-4x-5=0larrcolor(blue)"in standard form"#
#"the factors of - 5 which sum to - 4 are - 5 and + 1"#
#rArr(x-5)(x+1)=0#
#"equate each factor to zero and solve for x"#
#x+1=0rArrx=-1#
#x-5=0rArrx=5#
