How do you solve #((x-2)/5)=((10-x)/8)#? Algebra Rational Equations and Functions Clearing Denominators in Rational Equations 1 Answer G_Ozdilek Apr 25, 2017 #8(x-2)=5(10-x)# or #x=66/13# Explanation: Your equation is: #8x-16=50-5x# after some arrangement. Now you can get #8x+5x=50+16# #13x=66# #x=66/13# Answer link Related questions What is Clearing Denominators in Rational Equations? How do you solve rational expressions by multiplying by the least common multiple? How do you solve #5x-\frac{1}{x}=4#? How do you solve #-3 + \frac{1}{x+1}=\frac{2}{x}# by finding the least common multiple? What is the least common multiple for #\frac{x}{x-2}+\frac{x}{x+3}=\frac{1}{x^2+x-6}# and how do... How do you solve #\frac{x}{x^2-36}+\frac{1}{x-6}=\frac{1}{x+6}#? How do you solve by clearing the denominator of #3/x+2/x^2=4#? How do you solve #2/(x^2+2x+1)-3/(x+1)=4#? How do you solve equations with rational expressions #1/x+2/x=10#? How do you solve for y in #(y+5)/ 2 - y/3 =1#? See all questions in Clearing Denominators in Rational Equations Impact of this question 3133 views around the world You can reuse this answer Creative Commons License