How do you solve #x^2=5#? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 2 Answers Camilleon May 14, 2018 Answer: #x# = #sqrt(5)#, also expressed as 2.2360679775 Explanation: #x^2 = 5# In order to solve this, you just need to find the square root of five. #x# = #sqrt(5)# #sqrt(5)# = 2.2360679775 Kushagra May 14, 2018 IF #x^2=5# Then #sqrt(x^2)=sqrt5# #x=sqrt5# #x~~2.2# Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 753 views around the world You can reuse this answer Creative Commons License