# How do you solve  (x^2 - 5)/(x + 3) = 0?

Mar 26, 2016

I found: $x = \pm \sqrt{5}$

#### Explanation:

We need to find the value(s) of $x$ that satisfy our equation; we also need to avoid $x$ values that make our relationship INDETERMINATE!
This is because if you make the denominator zero (choosing $x = - 3$) the division by zero is not possible!
So as first consideration we say that:
$x \ne - 3$
Next we solve our equation:

${x}^{2} - 5 = 0 \cdot \left(x + 3\right)$
moving the denominator to the right of the equal sign;
so:
${x}^{2} - 5 = 0$
${x}^{2} = 5$
$x = \pm \sqrt{5}$