Question

How do you solve `x^2 - 5x =0`?

Answer 1

Factorize `x` as common
`x(x-5)=0`

Divide both sides by `x`
`x-5=0`( as `0/x=0`)

Transfer the `5`
`x=5`
Voila!

Answer 2

see below

Explanation:

We have, `x^2-5x=0`
`x(x-5)=0`
Thus,either `x` can be `0` or it can be `5`