# How do you solve x^2 - 5x =0?

May 14, 2018

Factorize $x$ as common
$x \left(x - 5\right) = 0$

Divide both sides by $x$
$x - 5 = 0$( as $\frac{0}{x} = 0$)

Transfer the $5$
$x = 5$
Voila!

May 14, 2018

see below

#### Explanation:

We have, ${x}^{2} - 5 x = 0$
$x \left(x - 5\right) = 0$
Thus,either $x$ can be $0$ or it can be $5$