Question

How do you solve `x^2-5x=-20` solve equation using quadratic formula?

Answer 1

`x=(5+-isqrt(55))/2`

Explanation:

Given -

`x^2-5x=-20`

`x^2-5x+20=0`

`x=(-b+-sqrt(b^2-4ac))/(2a)`

`x=(-(-5)+-sqrt((-5)^2-(4 xx 1 xx 20)))/(2 xx 1)`

`x=(5+-sqrt((25-80)))/2`

`x=(5+-sqrt(-55))/2`

`x=(5+sqrt(-55))/2`
`x=(5-sqrt(-55))/2`

`x=(5+-isqrt(55))/2`