How do you solve x^2-5x+4=0?

Apr 9, 2016

$x = 4$ or $x = 1$

Explanation:

${x}^{2} - 5 x + 4 = 0$

We need to factorize it:

${x}^{2} - x - 4 x + 4 = 0$

$x \left(x + 1\right) - 4 \left(x - 1\right) = 0$

$\left(x - 4\right) \left(x - 1\right) = 0$

$x - 4 = 0$ or $x - 1 = 0$

$x = 4$ or $x = 1$