# How do you solve x^2 = -5x - 5?

Jun 10, 2016

$x = \frac{- 5 \pm \sqrt{5}}{2}$

#### Explanation:

First, bring the equation to standard form:
$y = {x}^{2} + 5 x + 5 = 0$
$D = {d}^{2} = {b}^{2} - 4 a c = 25 - 20 = 5$ --> $d = \pm \sqrt{5}$
$x = - \frac{b}{2 a} \pm \frac{d}{2 a} = - \frac{5}{2} \pm \frac{\sqrt{5}}{2} = \frac{- 5 \pm \sqrt{5}}{2}$