How do you solve #(x+2)/6 + (x-2)/10 = 6/5#?
A fraction's structure consists of :
You can NOT DIRECTLY add or subtract the counts unless the size indicators are the same.
Multiply by 1 and you do not change the intrinsic value. However, 1 comes in many forms so you can change the way a fraction looks without changing its intrinsic value.
Make all the denominators the same but insuring that the numerators remain proportional to the denominator.
Then just solve for the numerators only. This really works!
I choose to make the denominators 60:
Thus it also true that:
Subtract 8 from both sides
Divide both sides by 16
If you have fractions which are in an equation, you can get rid of them immediately.
Multiply each term by the LCM of the denominators. (In this case
If you multiply the whole equation by
Now cancel each denominator.