# How do you solve #x^2+6x-16=0#?

##### 1 Answer

Mar 27, 2016

#### Explanation:

Find two factors of

Hence we find:

#0 = x^2+6x-16 = (x+8)(x-2)#

So

Alternatively, complete the square then use the difference of squares identity:

#a^2-b^2 = (a-b)(a+b)#

with

#0 = x^2+6x-16#

#=(x+3)^2-9-16#

#=(x+3)^2-25#

#=(x+3)^2-5^2#

#=((x+3)-5)((x+3)+5)#

#=(x-2)(x+8)#

Hence zeros