Question

How do you solve `x^2-6x-5=0` using the quadratic formula?

Answer 1

x=`3+-sqrt(14)`

Explanation:

Solution of quadratic equation `ax^2 +bx +c=0` is,

x= `(-b+-sqrt(b^2-4ac))/(2a)`. This is known as the quadratic formula.

The solution of the given equation would be x= `(6+-sqrt(36+20))/2`

x=`3+-sqrt(14)`