Question

How do you solve `x^2+ 6x - 72 = 0`?

Answer 1

6 and -12

Explanation:

`y = x^2 + 6x - 72 = 0`.
Find 2 numbers knowing sum (-b = -6) and product (c = -72).
Factor pairs of (c = -72) --> (-4, 18)(4, -18)(-6, 12)(6, -12). This sum is
(-6 = -b).
Then, the 2 real roots are : 6 and -12