Question

How do you solve `x^2-7+12=0`?

Answer 1

I am not sure about the question. I think it should be `x^2-7x+12=0`.

Explanation:

Case 1 (I do not think it is the right one).
`x^2-7+12=0`
`x^2=-5`
`x=+-sqrt(5)*i`
Where `i=sqrt(-1)`

Case 2
`x^2-7x+12=0`

Use the Quadratic Formula:

`x_(1,2)=(7+-sqrt(49-48))/2=(7+-1)/2`
Two solutions:
`x_1=4`
`x_2=3`