How do you solve #x^2+7x+10=0#?

1 Answer
Mar 22, 2016

Answer:

#x=-2#
#x=-5#

Explanation:

#x^2+7x+10=0#

We could right the equation in another form using brackets.

#(x+2)(x+5)=0#

In order to get two numbers to multiply and give 0, at least one number has to be 0.

a stands for the first bracket and b for the second.
a x b = 0
a=0 or b=0 to make this equation valid.

Therefore x= -2 or x= -5 because -2+2=0 and -5+5=0 according to both brackets.