How do you solve #x^2/81-6=-2# using any method?

1 Answer
Mar 7, 2018

Answer:

#x=+-18#

Explanation:

#"add 6 to both sides"#

#x^2/81cancel(-6)cancel(+6)=-2+6#

#rArrx^2/81=4#

#"to eliminate the fraction multiply both sides by "81#

#cancel(81)xx x^2/cancel(81)=81xx4#

#rArrx^2=324#

#color(blue)"take square root of both sides"#

#x=+-sqrt324larrcolor(blue)"note plus or minus"#

#rArrx=+-18" is the solution"#