How do you solve x^2 = 8x – 12?

1 Answer
Jun 7, 2015

x²=8x-12
x²-8x+12=0 ( we substract 8x-12 on each side )
This is an equation of the form ax²+bx+c=0
a=1
b=-8
c=12

We can know calculate Delta :

Delta=b²-4ac
Delta=(-8)²-4*1*12
Delta=64-48
Delta=16 (=4²)

x_1=(-b-sqrtDelta)/(2a)

x_1=(8-4)/2

x_1=4/2

x_1=2

x_2=(-b+sqrtDelta)/(2a)

x_2=(8+4)/2

x_2=12/2

x_2=6

Thus : x=2 or x=6