How do you solve x^2 - 8x = -16?

x has equal roots : $x = 4$
${x}^{2} - 8 x + 16 = 0 \mathmr{and} {\left(x - 4\right)}^{2} = 0 \mathmr{and} \left(x - 4\right) \left(x - 4\right) = 0 \therefore x = 4 \mathmr{and} x = 4$[Ans]