Question

How do you solve `x^2 + 8x – 48 = 0` by completing the square?

Answer 1

`x=-12`
`x=4`

Explanation:

`x^2+8x-48=0`
or
`x^2+12x-4x-48=0`
or
`x(x+12)-4(x+12)=0`
or
`(x+12)(x-4)=0`
or
`x+12=0`
or
`x=-12`
or
`x-4=0`
or
`x=4`