# How do you solve x^2 + 8x – 48 = 0 by completing the square?

Jul 31, 2016

$x = - 12$
$x = 4$

#### Explanation:

${x}^{2} + 8 x - 48 = 0$
or
${x}^{2} + 12 x - 4 x - 48 = 0$
or
$x \left(x + 12\right) - 4 \left(x + 12\right) = 0$
or
$\left(x + 12\right) \left(x - 4\right) = 0$
or
$x + 12 = 0$
or
$x = - 12$
or
$x - 4 = 0$
or
$x = 4$