Question

How do you solve `x^2+8x-5=0`?

Answer 1

For a quadratic equation of the form `ax^2+bx+c = 0`
the solutions are given by the quadratic formula
`x= (-b+-sqrt(b^2-4ac))/(2a)`

For `x^2+8x-5 = 0`
this becomes

`(-8+-sqrt(64+20))/2`

`=-4+-sqrt(21)`