How do you solve #x- 2\leq 7- 3x#?

1 Answer
Abhishek K.
Dec 26, 2016

#x<=9/4# or #2 1/4#

Explanation:

#x-2<=7-3x#

or, #x+3x-2<=7-3x+3xrarr#Subtract #3x# from both sides

or, #4x-2+2<=7+2rarr#Add #2# on both sides.

or, #4x<=9#

or, #(4x)/4<=9/4rarr#Divide both sides by #4#.

or, #x<=9/4 or 2 1/4#

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