# How do you solve #x^2 + x + 1=0# by completing the square?

##### 2 Answers

May 4, 2015

Since D = b^2 - 4ac = 1 - 4 = -3 < 0, there are complex roots.

May 4, 2015

In this way:

that is an impossible equation (no solutions) because a square can't be negative.