How do you solve $x - 2 (x + 10) = 12$ $x-2(x+10)=12$ ?

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Answer 1 · 2018-05-10T21:37:53

$x = - 32$ $x=-32$

Expand the brackets

$x - 2 (x + 10) = 12 \Rightarrow x - 2 x - 20 = 12$ $x-2(x + 10)=12 => x-2x-20=12$

$- x - 20 = 12$ $-x-20=12$

Add $x$ $x$ to both sides

$- 20 = 12 + x$ $-20=12+x$

Subtract 12 from both sides

#-32=x

How do you solve x−2(x+10)=12x-2(x+10)=12?