How do you solve x^2-x+3=0 using the quadratic formula?

1 Answer
May 7, 2016

x =1/2+-sqrt(11)/2i

Explanation:

x^2-x+3=0 is in the form ax^2+bx+c=0 with a=1, b=-1 and c=3.

This has roots given by the quadratic formula:

x = (-b+-sqrt(b^2-4ac))/(2a)

=(1+-sqrt((-1)^2-(4*1*3)))/(2*1)

=(1+-sqrt(-11))/2

=(1+-sqrt(11)i)/2

=1/2+-sqrt(11)/2i