How do you solve #x^2-x+3=0# using the quadratic formula?
1 Answer
May 7, 2016
Explanation:
This has roots given by the quadratic formula:
#x = (-b+-sqrt(b^2-4ac))/(2a)#
#=(1+-sqrt((-1)^2-(4*1*3)))/(2*1)#
#=(1+-sqrt(-11))/2#
#=(1+-sqrt(11)i)/2#
#=1/2+-sqrt(11)/2i#
