# How do you solve #x^2/(x - 4) (-) 7/x - 4 = 0#?

##### 1 Answer

Assuming

and also assuming that the parentheses around the minus sign are extraneous.

We can write the equation with all terms on the left side having a common denominator of

Then things really get ugly:

- Substitute
#y+4/3# for#x# to get a depressed cubic equation (the equation won't be the only thing depressed when you're done with this) with the form y^3+Ay = B# - Find
#s# and#t# such that#3*s*t = A# and#s^3-t^3 = B# - Back-track to solve for
#x#

You will notice that I have not done any of this (at least not here; formatting the steps is at least as horrifying as working out the solution).

If you really need this continued, first, please verify the question and that my assumptions were correct