# How do you solve x^2/(x-4) - 7/(x-4) = 0?

$\to \frac{{x}^{2} - 7}{x - 4} = 0$
This will only be $= 0$ if the top part $= 0$
$\to {x}^{2} - 7 = 0 \to {x}^{2} = 7 \to x = \pm \sqrt{7}$ (two solutions)