How do you solve $(x-2)(x+5) = 18$ ?

Question

1376 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-06-04T02:58:46

$x = 4$ , $x = -7$

$(x - 2)(x + 5) = 18$

$=> x^2 + 3x - 10 = 18$

$=> x^2 + 3x - 28 = 0$

$=> (x + 7)(x - 4)$ = 0

$=> x + 7 = 0 => x = -7$
$=> x - 4 = 0 => x = 4$

How do you solve (x-2)(x+5) = 18(x-2)(x+5) = 18?