How do you solve #x^2=-x+7# using the quadratic formula?

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Answer 1 · 2016-02-25T20:05:21

The roots are #2.192582404# and #-3.192582404#

Re-arrange the equation into a standard form
#ax^2+bx+c=0#

in this case, that would be

1) #x^2+x-7=0#

Using the quadratic formula #(-b +-sqrt(b^2-4ac))/(2a)#

Substituting the values from equation into the general formula

#(-1 +-sqrt(1^2-4*1*-7))/(2*1)#

simplifies to
#(-1 +-sqrt(29))/(2)#

or #2.192582404# and #-3.192582404#