How do you solve $x^{2} + y^{2} = 153, y = - 4 x$ $x^2+y^2=153, y=-4x$ ?

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Answer 1 · 2016-12-10T21:08:25

$x = {- 3, + 3}$ $x={-3,+3}$

$x^{2} + y^{2} = 153$ $x^2+y^2=153$
$y = - 4 x$ $y=-4x$

$(y^{2}) = {(- 4)}^{2}$ $(y^2)=(-4)^2$
${(y)}^{2} = 16 x^{2}$ $(y)^2=16x^2$

$x^{2} + 16 x^{2} = 153$ $x^2+16x^2=153$
$17 x^{2} = 153$ $17x^2=153$

$x^{2} = \frac{153}{17}$ $x^2=153/17$

$x^{2} = 9$ $x^2=9$

$x = {- 3, + 3}$ $x={-3,+3}$

How do you solve x2+y2=153,y=−4xx^2+y^2=153, y=-4x?