How do you solve x=2y2 and 3xy=14 using substitution?

1 Answer
Apr 27, 2018

(x,y)(6,4)

Explanation:

x=2y2(1)

3xy=14(2)

equation (1) expresses x in terms of y

Substitute x=2y2 into equation (2)

3(2y2)y=14

6y6y=14

5y6=14

add 6 to both sides

5y=20y=205=4

substitute y=4 into equation (1)

x=(2×4)2=6

the point of intersection of the 2 equations =(6,4)
graph{(y-1/2x-1)(y-3x+14)((x-6)^2+(y-4)^2-0.04)=0 [-10, 10, -5, 5]}