How do you solve x=2y−2 and 3x−y=14 using substitution?
1 Answer
Apr 27, 2018
Explanation:
x=2y−2→(1)
3x−y=14→(2)
equation (1) expresses x in terms of y
Substitute x=2y−2 into equation (2)
⇒3(2y−2)−y=14
⇒6y−6−y=14
⇒5y−6=14
add 6 to both sides
⇒5y=20⇒y=205=4
substitute y=4 into equation (1)
⇒x=(2×4)−2=6
the point of intersection of the 2 equations =(6,4)
graph{(y-1/2x-1)(y-3x+14)((x-6)^2+(y-4)^2-0.04)=0 [-10, 10, -5, 5]}