How do you solve #x+2y=5# and #2x-2y=4#?

1 Answer
Aug 3, 2015

Answer:

The solution for the system of equations is
#color(blue)(x=3,y=1#

Explanation:

#x+color(blue)(2y)=5 # .....equation #(1)#
#2x−color(blue)(2y)=4#....equation #(2)#

We can solve the equations through elimination
Adding the two equations results in elimination of #color(blue)(2y#

#x+cancelcolor(blue)(2y)=5 #
#2x−cancelcolor(blue)(2y)=4#

#3x=9#
#color(blue)(x=3#

Substituting #x# in equation #1# to find #y#
#x+2y=5 #
#2y=5-x #
#2y=5-3 #
#color(blue)(y=1#