How do you solve #-x + 2y = 6# and #x + 4y =24#?

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Answer 1 · 2016-03-14T17:58:02

The solution for the system of equations is:
#color(blue)(x=4#
#color(blue)(y=5#

#color(blue)(-x) + 2y = 6# ..............equation #(1)#
#color(blue)( x) +4y=24#.................equation #(2)#

Solving by elimination.

Adding equations #1# and #2# results in elimination of #color(blue)( x)#

#cancelcolor(blue)(-x) + 2y = 6#
#cancelcolor(blue)( x) +4y=24#

#6y= 30#

#y = 30/6#

#color(blue)(y=5#

Finding #x # from equation #(1)#:
#-x + 2y = 6#

# 2y - 6 = x#

# 2 *color(blue)( 5) - 6 = x#

# 10 - 6 = x#

#color(blue)(x=4#