# How do you solve x² - 3 = 0 using the quadratic formula?

For a quadratic with formula $a {x}^{2} + b c + c = 0$ the solutions are given by
${x}_{1 , 2} = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$
Now for ${x}^{2} - 3 = 0$ we have $a = 1 , b = 0 , c = - 3$ hence
${x}_{1 , 2} = \frac{0 \pm \sqrt{{0}^{2} - 4 \cdot 1 \left(- 3\right)}}{2} = \pm \sqrt{3}$