How do you solve #x^3 - 10x^2 +24x = 0 #?

2 Answers
Apr 7, 2018

Answer:

#x=0 or 4 or 6#

Explanation:

#x^3-10x^2+24x=0#

Factor,

#x(x^2-10x+24)=0#

Factor,

#x(x-6)(x-4)=0#

Hence,

#x=0 or 4 or 6#

Apr 7, 2018

Answer:

#x=0,x=4,x=6#

Explanation:

#"take out a "color(blue)"common factor " x#

#x(x^2-10x+24)=0#

#"the factors of + 24 which sum to - 10 are - 4 and - 6"#

#rArrx(x-4)(x-6)=0#

#"equate each factor to zero and solve for x"#

#rArrx=0#

#rArrx-4=0rArrx=4#

#x-6=0rArrx=6#