How do you solve #x^(3/2) - 10x^(1/2) = 0 #?

Question

1412 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-10-20T15:16:00

#x=0# OR #x=10#

We can factor out fractional exponents. Since the base #(x)# is the same.

Look at the fractional exponent that is the least and proceed as follows:

Remember your properties for exponents #x^mx^n=x^(m+n)#

#x^(1/2)[x^(2/2)-10]=0#

#x^(1/2)[x-10]=0#

#x^(1/2)=0# OR #x-10=0#

So #x=0# OR #x=10#