How do you solve $(x - 3)^2 = 25$ ?

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Answer 1 · 2016-04-13T18:10:57

$=>x=8 or x=-2$

Take the square root of both sides giving

$sqrt( (x-3)^2) = +-sqrt(25)$

Technically it should be $+-sqrt( (x-3)^2) = +-sqrt(25)$

But the same answer would be obtained by

$sqrt( (x-3)^2) = +-sqrt(25)$

$=> x-3=+-5$

$=> x=3+-5$

$=>x=8 or x=-2$

How do you solve (x - 3)^2 = 25(x - 3)^2 = 25?