# How do you solve x^3 + 27 = 0?

Then teach the underlying concepts
Don't copy without citing sources
preview
?

#### Explanation

Explain in detail...

#### Explanation:

I want someone to double check my answer

1
Nickola Share
Mar 14, 2018

#### Explanation:

Subtract 27 from each side
You should have ${x}^{3}$=-27
Take the cubed root of each side.
Answer is -3. (Any odd number root (${x}^{1} , {x}^{3} , {x}^{5} ,$..., ect.) can have negative answers.)

Then teach the underlying concepts
Don't copy without citing sources
preview
?

#### Explanation

Explain in detail...

#### Explanation:

I want someone to double check my answer

1
Kha L. Share
Mar 14, 2018

$x = - 3$

#### Explanation:

First, you subtract $27$ off both sides.
${x}^{3} + 27 = 0$
${x}^{3} = - 27$

Then, you take the cube root of both sides.
$\sqrt[3]{{x}^{3}} = \sqrt[3]{- 27}$
$x = - 3$

$\sqrt[3]{- 27} = - 3$ because...
$- 3 \cdot - 3 \cdot - 3 = - 27$

• 55 minutes ago
• 57 minutes ago
• 58 minutes ago
• 58 minutes ago
• 7 minutes ago
• 9 minutes ago
• 33 minutes ago
• 47 minutes ago
• 54 minutes ago
• 55 minutes ago
• 55 minutes ago
• 57 minutes ago
• 58 minutes ago
• 58 minutes ago