# How do you solve x^3 + 27 = 0?

Mar 14, 2018

$x = - 3$

#### Explanation:

First, you subtract $27$ off both sides.
${x}^{3} + 27 = 0$
${x}^{3} = - 27$

Then, you take the cube root of both sides.
$\sqrt[3]{{x}^{3}} = \sqrt[3]{- 27}$
$x = - 3$

$\sqrt[3]{- 27} = - 3$ because...
$- 3 \cdot - 3 \cdot - 3 = - 27$

Mar 14, 2018

You should have ${x}^{3}$=-27
Answer is -3. (Any odd number root (${x}^{1} , {x}^{3} , {x}^{5} ,$..., ect.) can have negative answers.)