How do you solve #x^3 + 27 = 0#?

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Nickola Share
Mar 14, 2018

Answer:

The answer is -3.

Explanation:

Subtract 27 from each side
You should have #x^3#=-27
Take the cubed root of each side.
Answer is -3. (Any odd number root (#x^1,x^3,x^5,#..., ect.) can have negative answers.)

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Write your answer here...
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Answer

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Answer:

Explanation

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Kha L. Share
Mar 14, 2018

Answer:

#x=-3#

Explanation:

First, you subtract #27# off both sides.
#x^3+27=0#
#x^3=-27#

Then, you take the cube root of both sides.
#root(3)(x^3)=root(3)(-27)#
#x=-3#

#root(3)(-27)=-3# because...
#-3*-3*-3=-27#

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