Question

How do you solve `x^3-2x^2-x+2=0`?

Answer 1

`x=2 ; x=1; x=-1`

Explanation:

`x^3-2x^2-x+2=0 or x^3-x^2-x^2+x-2x+2=0 or x^2(x-1)-x(x-1)-2(x-1)=0`
or `(x^2-x-2)(x-1)=0 or (x^2+x-2x-2)(x-1)=0 or (x(x+1)-2(x+1))(x-1)=0` or
`(x-2)(x+1)(x-1)=0 :. x=2 ; x=1; x=-1`[Ans]