# How do you solve (x-3)/(5)+(2x+1)/(4)=6/(10)?

The solution is $x = \frac{19}{14}$.
First, you have to make a common denominator for both members of the equation. The minimum common multiplier of 5, 4 and 10 is 20. So you write the equation as (4(x-3))/20 + (5(2x+1))/20 = (2·6)/20, and then, operating, you obtain: $\frac{4 x - 12}{20} + \frac{10 x + 5}{20} = \frac{12}{20}$. And operating the similar terms you obtain: $\frac{14 x - 7}{20} = \frac{12}{20}$.
Now you must work only with the numerators making: $14 x - 7 = 12 \implies 14 x = 19 \implies x = \frac{19}{14}$.