Question

How do you solve `x^3+8x^2=-16x`?

Answer 1

`x=0color(white)("XX")orcolor(white)("XX")x=-4`

Explanation:

If `x!=0` we can divide both sides by `x`
So
#{: ("either",x=0,color(white)("XX")orcolor(white)("XX"),x^2+8x=-16), (,,,rarr x^2+8x+16=0), (,,,rarr (x+4)^2=0), (,,,rarr x=-4) :}#