# How do you solve x-(3/x) = -2?

May 22, 2015

You can start by lowest common denominator

$\frac{x \cdot x - 3 \cdot 1}{x} = - 2$
$\frac{{x}^{2} - 3}{x} = - 2$
${x}^{2} - 3 = - 2 x$
${x}^{2} + 2 x - 3 = 0$

Now, just find the roots:

$\frac{- 2 \pm \sqrt{4 - 4 \left(1\right) \left(- 3\right)}}{2}$
$\frac{- 2 \pm 4}{2}$
${x}_{1} = - 3$
${x}_{2} = 1$