How do you solve #x/3+ x/4=1#?
1 Answer
Oct 4, 2016
Explanation:
The LCM (lowest common multiple) of 3 and 4 is 12.
Multiplying
#color(blue)"All"# terms on both sides of the equation by 12 will eliminate the fractions.
#cancel(12)^4xxx/cancel(3)^1+cancel(12)^3xxx/cancel(4)^1=(1xx12)# which simplifies to.
#4x+3x=12rArr7x=12# To solve for x divide both sides by 7.
#(cancel(7) x)/cancel(7)=12/7#
#rArrx=12/7" is the solution"#