How do you solve (x-3)(x-5)(x+1)=0?

Jan 25, 2018

$\textcolor{b l u e}{x = 3 , 5 , - 1}$

Explanation:

$\left(x - 3\right) \cdot \left(x - 5\right) \cdot \left(x + 1\right) = 0$

i.e. $x - 3 = 0 \mathmr{and} x - 5 = 0 \mathmr{and} x + 1 = 0$

Case 1 : $x - 3 = 0 , \textcolor{g r e e n}{x = 3}$

Case 2 : $x - 5 = 0 , \textcolor{g r e e n}{x = 5}$

Case 3 : $x + 1 = 0 , \textcolor{g r e e n}{x = - 1}$