How do you solve #(x-3)(x-5)(x+1)=0#? Precalculus Polynomial Functions of Higher Degree Zeros 1 Answer sankarankalyanam Jan 25, 2018 #color(blue)(x = 3, 5, -1)# Explanation: #(x-3) * (x-5) * (x+1) = 0# i.e. #x-3 =0 or x-5 = 0 or x+1 = 0# Case 1 : #x - 3 = 0, color(green)(x = 3)# Case 2 : #x - 5 = 0, color(green)(x = 5)# Case 3 : #x + 1 = 0, color(green)(x = -1)# Answer link Related questions What is a zero of a function? How do I find the real zeros of a function? How do I find the real zeros of a function on a calculator? What do the zeros of a function represent? What are the zeros of #f(x) = 5x^7 − x + 216#? What are the zeros of #f(x)= −4x^5 + 3#? How many times does #f(x)= 6x^11 - 3x^5 + 2# intersect the x-axis? What are the real zeros of #f(x) = 3x^6 + 1#? How do you find the roots for #4x^4-26x^3+50x^2-52x+84=0#? What are the intercepts for the graphs of the equation #y=(x^2-49)/(7x^4)#? See all questions in Zeros Impact of this question 2365 views around the world You can reuse this answer Creative Commons License