How do you solve #x( 3x - 29) = - 26#?

2 Answers
Apr 4, 2018

Answer:

#x=26/6, x=1#

Explanation:

Expand out.
#x(3x-29)=-26#
#3x^2-29x=-26#

Move -26 over, gives a quadratic equation
#3x^2-29x+26=0#

Factorise / graphically derive roots
#(3x-26)(x-1)#
graph{3x^2-29x+26 [-10, 10, -5, 5]}

#x=26/3, x=1#

Apr 4, 2018

Answer:

#x = 26/3 or x = 1 #

Explanation:

#3x^2 - 29x = -26#

#3x^2 - 29x - (-26) = -26 (-26)#

#3x^2 - 29x + 26 = 0#

#(3x - 26)(x-1) = 0#

So

# 3x−26=0 or x−1=0#

#x= 26/3 or x=1#