How do you solve #x + 3y = -1# and #6x + 4y = -6#?

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Answer 1 · 2018-05-27T11:29:14

Solution : # x =-1 , y=0#

#x+3 y = -1 ; (1) , 6 x +4 y = -6 ; (2)# Multiplying equation (1)

by #6# on both sides we get , # 6 x+18 y = -6 ; (3) # Subtracting

equation (2) from equation (3 ) we get ,

# (6 x+18 y) - (6 x +4 y ) = -6 - (-6) # or

# cancel (6 x)+18 y - cancel (6 x) -4 y = cancel(-6) +cancel 6 # or

# 14 y =0 :. y=0# . Putting #y=0# in equation (1) we get,

#x+0=-1 :. x =-1#

Solution # x =-1 , y=0# [Ans]