How do you solve # x+3y=11# and #x+4y=14#?

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Answer 1 · 2015-08-02T14:04:57

The solution for the system of equations is
#color(green)(x=2,y=3#

#x+3y=11 #
#x=color(green)(11-3y#....equation #(1)#

#x+4y=14#...equation #(2)#

Substituting equation#(1)# in equation #(2)# to find #y#

#x+4y=14#

#color(green)(11-3y+4y=14#

#11-3y+4y=14#

#11+y=14#

#color(green)(y=3#

Substituting the value of #y# in equation #(1) #to find #x#

#x=11 -3y#

#x=11-3*3#

#color(green)(x=2#