How do you solve x+3y=-2, 2x-y=10?

1 Answer
Sep 8, 2015

Answer:

The solutions for the system of equations is
#color(blue)(x=4, y=-2#

Explanation:

#x+3y=-2#, multiplying this equation by #2#
#color(blue)(2x)+6y=-4#......equation #1#

#color(blue)(2x)-y=10#.....equation #2#

Solving by elimination.

Subtracting equation #2# from #1# results in elimination of #color(blue)(2x#

#cancelcolor(blue)(2x)+6y=-4#
#-cancelcolor(blue)(2x)+y=-10#
#7y =-14#
#color(blue)(y=-2#

Finding #x# by substituting #y# in equation #1#
#x+3y=-2#
#x+3*(-2)=-2#
#x-6=-2#
#x=-2+6#
#color(blue)(x=4#