# How do you solve x + 3y = 24 and 2x + 6y= 48?

In order to solve systems of equations in two variables, one of the equations cannot be the factor of the other. In the equations you gave, $2 x + 6 y = 48$ is the double of $x + 3 y = 24$. So we'd know $x + 3 y = 48$ even if the only equation we knew was $2 x + 6 y = 48$, because that's what you get when you divide it by $2$.