# How do you solve x-3y=9 and 2x-6y=10 using substitution?

Jul 17, 2016

$x = 9 + 3 y$

$2 \left(9 + 3 y\right) - 6 y = 10$

$18 + 6 y - 6 y = 10$

$0 y = - 8$

$y = \emptyset$

Hence, this system has no solution because the two lines are parallel.

Hopefully this helps!