# How do you solve (x + 4)^2 = 11?

Oct 29, 2015

$x = - 4 - \sqrt{11} \textcolor{w h i t e}{\text{XXX}}$or$\textcolor{w h i t e}{\text{XXX}} x = - 4 + \sqrt{11}$

#### Explanation:

Given
$\textcolor{w h i t e}{\text{XXX}} {\left(x + 4\right)}^{2} = 11$

then
$\textcolor{w h i t e}{\text{XXX}} x + 4 = \pm \sqrt{11}$
and
$\textcolor{w h i t e}{\text{XXX}} x = - 4 \pm \sqrt{11}$