How do you solve #-x/4 = (2x)/3#?

2 Answers
Mar 10, 2018

Answer:

#0=x#

Explanation:

#-x/4=(2x)/3|+x/4#
#0=(2x)/3+x/4#
#0=(11x)/12|*12/11#
#0=x#

Mar 10, 2018

Answer:

See a solution process below:

Explanation:

First, multiply each side of the equation by #color(red)(12)# to eliminate the fractions while keeping the equation balanced:

#color(red)(12) xx -x/4 = color(red)(12) xx (2x)/3#

#cancel(color(red)(12))color(red)(3) xx -x/color(red)(cancel(color(black)(4))) = cancel(color(red)(12))color(red)(4) xx (2x)/color(red)(cancel(color(black)(3)))#

#color(red)(3) xx -x = color(red)(4) xx 2x#

#-3x = 8x#

Next, add #color(red)(3x)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#-3x + color(red)(3x) = 8x + color(red)(3x)#

#0 = (8 + color(red)(3))x#

#0 = 11x#

Now, divide each side of the equation by #color(red)(11)# to solve for #x# while keeping the equation balanced:

#0/color(red)(11) = (11x)/color(red)(11)#

#0 = (color(red)(cancel(color(black)(11)))x)/cancel(color(red)(11))#

#0 = x#

#x = 0#